What is the inverse of f(x)=ln((e^x)/(e^{x-1)}) ?

The inverse of f(x)=ln((e^x)/(e^{x-1)}) is None

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inverse of f(x)=ln((e^x)/(e^{x-1)})

inverse

f (x) = ln (\frac{e ^{x}}{e ^{x - 1}})

None

Solution steps

y = ln (\frac{e ^{x}}{e ^{x - 1}})

Replace

x

with

y

x = ln (\frac{e ^{y}}{e ^{y - 1}})

Solve for

y, x = ln (\frac{e ^{y}}{e ^{y - 1}})

Therefore, there are no inverse functions for

ln (\frac{e ^{x}}{e ^{x - 1}})

None

\frac{9 x + 2}{x - 5}

f (x) = \frac{3 + e ^{2 x}}{5}

\frac{2}{8}

f (x) = \frac{7}{x + 1} - 9

f (x) = \frac{1 + 2 x}{6 - 5 x}

What is the inverse of f(x)=ln((e^x)/(e^{x-1)}) ?
The inverse of f(x)=ln((e^x)/(e^{x-1)}) is None