What is the inverse of f(x)=((x+3))/(x-7) ?

The inverse of f(x)=((x+3))/(x-7) is (3+7x)/(x-1)

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inverse of f(x)=((x+3))/(x-7)

inverse

f (x) = \frac{( x + 3 )}{x - 7}

\frac{3 + 7 x}{x - 1}

Solution steps

y = \frac{x + 3}{x - 7}

Replace

x

with

y

x = \frac{y + 3}{y - 7}

Solve for

y, x = \frac{y + 3}{y - 7}

\frac{3 + 7 x}{x - 1}

f (x) = (\frac{3}{x + 2})

\frac{4}{( s - 1 ) ^{3}}

\frac{x + 3}{x - 2}

f (x) = 7 - x + 9

f (x) = (6 x - 1)^{2}

What is the inverse of f(x)=((x+3))/(x-7) ?
The inverse of f(x)=((x+3))/(x-7) is (3+7x)/(x-1)