What is the inverse of (s+2)/(s^2+25) ?

The inverse of (s+2)/(s^2+25) is (1+sqrt(1-4s(25s-2)))/(2s),(1-sqrt(1-4s(25s-2)))/(2s)

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inverse of (s+2)/(s^2+25)

inverse

\frac{s + 2}{s ^{2} + 25}

\frac{1 + 1 - 4 s ( 25 s - 2 )}{2 s}, \frac{1 - 1 - 4 s ( 25 s - 2 )}{2 s}

Solution steps

y = \frac{s + 2}{s ^{2} + 25}

Replace

s

with

y

s = \frac{y + 2}{y ^{2} + 25}

Solve for

y, s = \frac{y + 2}{y ^{2} + 25}

\frac{1 + 1 - 4 s ( 25 s - 2 )}{2 s}, \frac{1 - 1 - 4 s ( 25 s - 2 )}{2 s}

f (x) = - \frac{1}{32} x^{2} - \frac{1}{8} x + \frac{3}{8}

f (x) = 30 x^{6}

- 6.5

\frac{( x + 5 )}{27}

f (x) = \frac{4 x - 3}{- 4 x}

What is the inverse of (s+2)/(s^2+25) ?
The inverse of (s+2)/(s^2+25) is (1+sqrt(1-4s(25s-2)))/(2s),(1-sqrt(1-4s(25s-2)))/(2s)