What is the inverse of 3sqrt((3x+2)/(2x+1)) ?

The inverse of 3sqrt((3x+2)/(2x+1)) is (x^2-18)/(27-2x^2)

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inverse of 3sqrt((3x+2)/(2x+1))

inverse

3 \frac{3 x + 2}{2 x + 1}

\frac{x ^{2} - 18}{27 - 2 x ^{2}}

Solution steps

y = 3 \frac{3 x + 2}{2 x + 1}

Replace

x

with

y

x = 3 \frac{3 y + 2}{2 y + 1}

Solve for

y, x = 3 \frac{3 y + 2}{2 y + 1}

\frac{x ^{2} - 18}{27 - 2 x ^{2}}

f (x) = lo g_{- 1} (x)

f (x) = \frac{( 6 x - 6 )}{( 6 x + 1 )}

f (x) = arcsin (x^{2})

y = x^{2} + 12 x

f (x) = 6 (x - 1)

What is the inverse of 3sqrt((3x+2)/(2x+1)) ?
The inverse of 3sqrt((3x+2)/(2x+1)) is (x^2-18)/(27-2x^2)