What is the inverse of f(x)=(x-8)^2+2 ?

The inverse of f(x)=(x-8)^2+2 is sqrt(x-2)+8,-sqrt(x-2)+8

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inverse of f(x)=(x-8)^2+2

inverse

f (x) = (x - 8)^{2} + 2

x - 2 + 8, - x - 2 + 8

Solution steps

y = (x - 8)^{2} + 2

Replace

x

with

y

x = (y - 8)^{2} + 2

Solve for

y, x = (y - 8)^{2} + 2

x - 2 + 8, - x - 2 + 8

sin (\frac{120}{240 2})

f (x) = 16 sin (7 x)

\frac{x ^{3}}{6} + 6

y = \frac{3 x + 1}{11 x - 2}

f (x) = \frac{( 5 + x ^{2} )}{4}

What is the inverse of f(x)=(x-8)^2+2 ?
The inverse of f(x)=(x-8)^2+2 is sqrt(x-2)+8,-sqrt(x-2)+8