What is the inverse of 1/(1+10e^{-0.5t)} ?

The inverse of 1/(1+10e^{-0.5t)} is -(ln(\frac{1-t)/(10t))}{0.5}

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inverse of 1/(1+10e^{-0.5t)}

inverse

\frac{1}{1 + 10 e ^{- 0.5 t}}

- \frac{ln ( \frac{1 - t}{10 t} )}{0.5}

Solution steps

y = \frac{1}{1 + 10 e ^{- 0.5 t}}

Replace

t

with

y

t = \frac{1}{1 + 10 e ^{- 0.5 y}}

Solve for

y, t = \frac{1}{1 + 10 e ^{- 0.5 y}}

- \frac{ln ( \frac{1 - t}{10 t} )}{0.5}

f (x) = 3^{x - 2} + 7

f (x) = \frac{( x + 2 )}{( x ^{2} - 1 )}

\frac{4}{1 + x ^{2}}

(4 + 0.1 x) (100 - 5 x)

f (x) = (5 x - 3) + (- 8 x + 6) + (- 1 + 9 x)

What is the inverse of 1/(1+10e^{-0.5t)} ?
The inverse of 1/(1+10e^{-0.5t)} is -(ln(\frac{1-t)/(10t))}{0.5}