What is the inverse of f(x)=-1/2 (x^2-4x-20) ?

The inverse of f(x)=-1/2 (x^2-4x-20) is -(-4+sqrt(-8x+96))/2 ,-(-4-sqrt(-8x+96))/2

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inverse of f(x)=-1/2 (x^2-4x-20)

inverse

f (x) = - \frac{1}{2} (x^{2} - 4 x - 20)

- \frac{- 4 + - 8 x + 96}{2}, - \frac{- 4 - - 8 x + 96}{2}

Solution steps

y = - \frac{1}{2} (x^{2} - 4 x - 20)

Replace

x

with

y

x = - \frac{1}{2} (y^{2} - 4 y - 20)

Solve for

y, x = - \frac{1}{2} (y^{2} - 4 y - 20)

- \frac{- 4 + - 8 x + 96}{2}, - \frac{- 4 - - 8 x + 96}{2}

lo g_{7} (141)

y = x^{2} + 2 x + 8

\frac{x - 3}{7 x + 1}

\frac{2 x - 5}{5 x + 3}

What is the inverse of f(x)=-1/2 (x^2-4x-20) ?
The inverse of f(x)=-1/2 (x^2-4x-20) is -(-4+sqrt(-8x+96))/2 ,-(-4-sqrt(-8x+96))/2