What is the inverse of f(x)=2+1/((5-x)^2) ?

The inverse of f(x)=2+1/((5-x)^2) is -sqrt(1/(x-2))+5,sqrt(1/(x-2))+5

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inverse of f(x)=2+1/((5-x)^2)

inverse

f (x) = 2 + \frac{1}{( 5 - x ) ^{2}}

- \frac{1}{x - 2} + 5, \frac{1}{x - 2} + 5

Solution steps

y = 2 + \frac{1}{( 5 - x ) ^{2}}

Replace

x

with

y

x = 2 + \frac{1}{( 5 - y ) ^{2}}

Solve for

y, x = 2 + \frac{1}{( 5 - y ) ^{2}}

- \frac{1}{x - 2} + 5, \frac{1}{x - 2} + 5

f (x) = 8^{x} - 4

f (x) = \frac{8 x + 1}{16 x ^{2} - 4}

y = sin (6 x)

f (x) = 3 x + 11

f (x) = 3 x + 18

What is the inverse of f(x)=2+1/((5-x)^2) ?
The inverse of f(x)=2+1/((5-x)^2) is -sqrt(1/(x-2))+5,sqrt(1/(x-2))+5