What is the inverse of h(x)=(-15x-13)^2 ?

The inverse of h(x)=(-15x-13)^2 is -(sqrt(x)+13)/(15),-(-sqrt(x)+13)/(15)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of h(x)=(-15x-13)^2

inverse

h (x) = (- 15 x - 13)^{2}

- \frac{x + 13}{15}, - \frac{- x + 13}{15}

Solution steps

y = (- 15 x - 13)^{2}

Replace

x

with

y

x = (- 15 y - 13)^{2}

Solve for

y, x = (- 15 y - 13)^{2}

- \frac{x + 13}{15}, - \frac{- x + 13}{15}

f (x) = (x^{3} + 1)^{4}

f (x) = arccoth (x)

f (x) = \frac{2 x}{x - 1}

f (x) = 2 x^{2}, x \geq 0

f (x) = 7 x^{3} - 12

What is the inverse of h(x)=(-15x-13)^2 ?
The inverse of h(x)=(-15x-13)^2 is -(sqrt(x)+13)/(15),-(-sqrt(x)+13)/(15)