What is the inverse of-9(x+3)^2-9 ?

The inverse of-9(x+3)^2-9 is sqrt(-(x+9)/9)-3,-sqrt(-(x+9)/9)-3

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inverse of-9(x+3)^2-9

inverse

- 9 (x + 3)^{2} - 9

- \frac{x + 9}{9} - 3, - - \frac{x + 9}{9} - 3

Solution steps

y = - 9 (x + 3)^{2} - 9

Replace

x

with

y

x = - 9 (y + 3)^{2} - 9

Solve for

y, x = - 9 (y + 3)^{2} - 9

- \frac{x + 9}{9} - 3, - - \frac{x + 9}{9} - 3

f (x) = 4 x^{2} - 2 x + 1

f (x) = \frac{x ^{2} - 12 x - 60}{16}

1 a^{0}

7 x^{2} + 4 x - 3

\frac{x ^{2}}{4} + 1

What is the inverse of-9(x+3)^2-9 ?
The inverse of-9(x+3)^2-9 is sqrt(-(x+9)/9)-3,-sqrt(-(x+9)/9)-3