What is the inverse of f(x)=2-\sqrt[3]{x-8} ?

The inverse of f(x)=2-\sqrt[3]{x-8} is -x^3+6x^2-12x+16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2-\sqrt[3]{x-8}

inverse

- x^{3} + 6 x^{2} - 12 x + 16

Solution steps

Replace

x

with

y

Solve for

- x^{3} + 6 x^{2} - 12 x + 16

y = (\frac{( 1 + x )}{1 - x})

(x - 9)^{2} + 3

f (x) = \frac{x}{6 x + 5}

f (x) = \frac{1}{5} (3) - 6

f (x) = 7 x x

What is the inverse of f(x)=2-\sqrt[3]{x-8} ?
The inverse of f(x)=2-\sqrt[3]{x-8} is -x^3+6x^2-12x+16