What is the inverse of ((\frac{10-3y)/3)/(2)}{3} ?

The inverse of ((\frac{10-3y)/3)/(2)}{3} is -(18y-10)/3

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inverse of ((\frac{10-3y)/3)/(2)}{3}

inverse

\frac{\frac{\frac{10 - 3 y}{3}}{2}}{3}

- \frac{18 y - 10}{3}

Solution steps

y = \frac{\frac{\frac{10 - 3 y}{3}}{2}}{3}

Replace

y

with

y

y = \frac{\frac{\frac{10 - 3 y}{3}}{2}}{3}

Solve for

y, y = \frac{\frac{\frac{10 - 3 y}{3}}{2}}{3}

- \frac{18 y - 10}{3}

\frac{x + 4}{x - 9}

f (x) = \frac{x}{3} + 10

\frac{x}{7} + \frac{2}{7}

f (x) = \frac{( 1 - 3 x )}{x + 1}

\frac{5}{3 x + 2}

What is the inverse of ((\frac{10-3y)/3)/(2)}{3} ?
The inverse of ((\frac{10-3y)/3)/(2)}{3} is -(18y-10)/3