What is the inverse of pi/(s^2+10pis+24pi^2) ?

The inverse of pi/(s^2+10pis+24pi^2) is (-5pis+sqrt(pis(pis+1)))/s ,-(5pis+sqrt(pis(pis+1)))/s

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inverse of pi/(s^2+10pis+24pi^2)

inverse

\frac{π}{s ^{2} + 10 π s + 24 π ^{2}}

\frac{- 5 π s + π s ( π s + 1 )}{s}, - \frac{5 π s + π s ( π s + 1 )}{s}

Solution steps

y = \frac{π}{s ^{2} + 10 π s + 24 π ^{2}}

Replace

s

with

y

s = \frac{π}{y ^{2} + 10 π y + 24 π ^{2}}

Solve for

y, s = \frac{π}{y ^{2} + 10 π y + 24 π ^{2}}

\frac{- 5 π s + π s ( π s + 1 )}{s}, - \frac{5 π s + π s ( π s + 1 )}{s}

f (x) = \frac{- x - 4}{4 x + 3}

f (x) = \frac{x}{50}

f (x) = x^{2} + 12 x + 2

tan (\frac{\frac{3}{4}}{\frac{3}{4}})

What is the inverse of pi/(s^2+10pis+24pi^2) ?
The inverse of pi/(s^2+10pis+24pi^2) is (-5pis+sqrt(pis(pis+1)))/s ,-(5pis+sqrt(pis(pis+1)))/s