What is the inverse of f(x)=3x^2-7x+4 ?

The inverse of f(x)=3x^2-7x+4 is (7+sqrt(12x+1))/6 ,(7-sqrt(12x+1))/6

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inverse of f(x)=3x^2-7x+4

inverse

f (x) = 3 x^{2} - 7 x + 4

\frac{7 + 12 x + 1}{6}, \frac{7 - 12 x + 1}{6}

Solution steps

y = 3 x^{2} - 7 x + 4

Replace

x

with

y

x = 3 y^{2} - 7 y + 4

Solve for

y, x = 3 y^{2} - 7 y + 4

\frac{7 + 12 x + 1}{6}, \frac{7 - 12 x + 1}{6}

y = sin (π x)

y = - 4.3 (x - 4.772)^{2} + 8.255

f (x) = 3 x - 24

\frac{x ^{2} + 2 x}{2 x ^{2} - 7 x}

f (r) = \frac{( - 16 + r )}{4}

What is the inverse of f(x)=3x^2-7x+4 ?
The inverse of f(x)=3x^2-7x+4 is (7+sqrt(12x+1))/6 ,(7-sqrt(12x+1))/6