What is the inverse of f(x)=\sqrt[3]{x+4}+4 ?

The inverse of f(x)=\sqrt[3]{x+4}+4 is x^3-12x^2+48x-68

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inverse of f(x)=\sqrt[3]{x+4}+4

inverse

x^{3} - 12 x^{2} + 48 x - 68

Solution steps

Replace

x

with

y

Solve for

x^{3} - 12 x^{2} + 48 x - 68

\frac{( 3 x + 2 )}{( 2 x + 5 )}

f (s) = \frac{42}{s ^{4}}

x \cdot 4 - x^{2}

cos (- \frac{2}{9})

What is the inverse of f(x)=\sqrt[3]{x+4}+4 ?
The inverse of f(x)=\sqrt[3]{x+4}+4 is x^3-12x^2+48x-68