What is the inverse of f(x)=2log_{10}(4x-7)+1 ?

The inverse of f(x)=2log_{10}(4x-7)+1 is (10^{(x-1)/2}+7)/(4)

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inverse of f(x)=2log_{10}(4x-7)+1

inverse

f (x) = 2 lo g_{10} (4 x - 7) + 1

\frac{1 0 ^{\frac{x - 1}{2}} + 7}{4}

Solution steps

y = 2 lo g_{10} (4 x - 7) + 1

Replace

x

with

y

x = 2 lo g_{10} (4 y - 7) + 1

Solve for

y, x = 2 lo g_{10} (4 y - 7) + 1

\frac{1 0 ^{\frac{x - 1}{2}} + 7}{4}

arccos (3 + 2 x)

\frac{1}{x ^{2} - 4 x - 5}

f (x) = 16 x - 19

\frac{3 x}{7 - x}

f (x) = - 2 x^{3} - 7

What is the inverse of f(x)=2log_{10}(4x-7)+1 ?
The inverse of f(x)=2log_{10}(4x-7)+1 is (10^{(x-1)/2}+7)/(4)