What is the inverse of f(x)=(t^2+4t-12)/(t^2-9t+14) ?

The inverse of f(x)=(t^2+4t-12)/(t^2-9t+14) is (6+7t)/(t-1)

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inverse of f(x)=(t^2+4t-12)/(t^2-9t+14)

inverse

f (x) = \frac{t ^{2} + 4 t - 12}{t ^{2} - 9 t + 14}

\frac{6 + 7 t}{t - 1}

Solution steps

x = \frac{t ^{2} + 4 t - 12}{t ^{2} - 9 t + 14}

Replace

t

with

x

t = \frac{x ^{2} + 4 x - 12}{x ^{2} - 9 x + 14}

Solve for

x, t = \frac{x ^{2} + 4 x - 12}{x ^{2} - 9 x + 14}

\frac{6 + 7 t}{t - 1}

f (x) = \frac{1}{2} \cdot 1 0^{3 x}

y = 10 + 0.75 x

f (t) = ln (t)

f (x) = \frac{( 1 - 2 x )}{4}

y = \frac{3 x}{7 x + 4}

What is the inverse of f(x)=(t^2+4t-12)/(t^2-9t+14) ?
The inverse of f(x)=(t^2+4t-12)/(t^2-9t+14) is (6+7t)/(t-1)