What is the inverse of f(x)=2y-2y^2 ?

The inverse of f(x)=2y-2y^2 is -(-1+sqrt(-2y+1))/2 ,(sqrt(-2y+1)+1)/2

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inverse of f(x)=2y-2y^2

inverse

f (x) = 2 y - 2 y^{2}

- \frac{- 1 + - 2 y + 1}{2}, \frac{- 2 y + 1 + 1}{2}

Solution steps

x = 2 y - 2 y^{2}

Replace

y

with

x

y = 2 x - 2 x^{2}

Solve for

x, y = 2 x - 2 x^{2}

- \frac{- 1 + - 2 y + 1}{2}, \frac{- 2 y + 1 + 1}{2}

f (a) = 3 a + 5

3 x + 18

6 x - 8 + 6

f (x) = \frac{- 1}{- 1 - 2}

f (x) = x^{2} - 3 x + 7, x = 11

What is the inverse of f(x)=2y-2y^2 ?
The inverse of f(x)=2y-2y^2 is -(-1+sqrt(-2y+1))/2 ,(sqrt(-2y+1)+1)/2