What is the inverse of-5x^2+x ?

The inverse of-5x^2+x is -(-1+sqrt(1-20x))/(10),-(-1-sqrt(1-20x))/(10)

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inverse of-5x^2+x

inverse

- 5 x^{2} + x

- \frac{- 1 + 1 - 20 x}{10}, - \frac{- 1 - 1 - 20 x}{10}

Solution steps

y = - 5 x^{2} + x

Replace

x

with

y

x = - 5 y^{2} + y

Solve for

y, x = - 5 y^{2} + y

- \frac{- 1 + 1 - 20 x}{10}, - \frac{- 1 - 1 - 20 x}{10}

6 x + 7 - 9

- 219 \cdot (- 4)

sin (\frac{12}{16})

f (x) = \frac{x - 203.2}{203.2} \cdot 100

g (x) = - \frac{1}{2} (x + 3)

What is the inverse of-5x^2+x ?
The inverse of-5x^2+x is -(-1+sqrt(1-20x))/(10),-(-1-sqrt(1-20x))/(10)