What is the inverse of f(x)=((x-1)/(x+2)) ?

The inverse of f(x)=((x-1)/(x+2)) is (-1-2x)/(x-1)

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inverse of f(x)=((x-1)/(x+2))

inverse

f (x) = (\frac{x - 1}{x + 2})

\frac{- 1 - 2 x}{x - 1}

Solution steps

y = \frac{x - 1}{x + 2}

Replace

x

with

y

x = \frac{y - 1}{y + 2}

Solve for

y, x = \frac{y - 1}{y + 2}

\frac{- 1 - 2 x}{x - 1}

f (x) = ln (\frac{5 - x}{x + 2})

2^{2 - x}

h (x) = 2 x + 1, x \geq 0

y = - \frac{1}{2} x + \frac{4}{5}

f (x) = \frac{x + 9}{5}

What is the inverse of f(x)=((x-1)/(x+2)) ?
The inverse of f(x)=((x-1)/(x+2)) is (-1-2x)/(x-1)