What is the inverse of f(x)=(2x-3)/(3x+1) ?

The inverse of f(x)=(2x-3)/(3x+1) is (-3-x)/(3x-2)

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inverse of f(x)=(2x-3)/(3x+1)

inverse

f (x) = \frac{2 x - 3}{3 x + 1}

\frac{- 3 - x}{3 x - 2}

Solution steps

y = \frac{2 x - 3}{3 x + 1}

Replace

x

with

y

x = \frac{2 y - 3}{3 y + 1}

Solve for

y, x = \frac{2 y - 3}{3 y + 1}

\frac{- 3 - x}{3 x - 2}

f (x) = (\frac{e ^{x} + 9}{2})^{\frac{1}{2}}

tan (6 x)

(x - 1) (x - 7)

f (x) = 3 x - 1 g (x) = x^{3} + 1

f (x) = \frac{1}{12} (- x^{2} + 12 x - 32) + 0.25

What is the inverse of f(x)=(2x-3)/(3x+1) ?
The inverse of f(x)=(2x-3)/(3x+1) is (-3-x)/(3x-2)