What is the inverse of f(x)=((7x+3))/((x-5)) ?

The inverse of f(x)=((7x+3))/((x-5)) is (3+5x)/(x-7)

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inverse of f(x)=((7x+3))/((x-5))

inverse

f (x) = \frac{( 7 x + 3 )}{( x - 5 )}

\frac{3 + 5 x}{x - 7}

Solution steps

y = \frac{7 x + 3}{x - 5}

Replace

x

with

y

x = \frac{7 y + 3}{y - 5}

Solve for

y, x = \frac{7 y + 3}{y - 5}

\frac{3 + 5 x}{x - 7}

f (x) = d + 1

\frac{- 3 x + 4}{7 x + 9}

ln (4 x + 2)

(\frac{( 9 ( ( 5 x ^{7} - 7 ) ) 5 )}{4}) 9

f (x) = - 12 x^{2} + 5

What is the inverse of f(x)=((7x+3))/((x-5)) ?
The inverse of f(x)=((7x+3))/((x-5)) is (3+5x)/(x-7)