What is the inverse of f(x)=1-1/2 e^{-2bx} ?

The inverse of f(x)=1-1/2 e^{-2bx} is -(ln(-2x+2))/(2b)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=1-1/2 e^{-2bx}

inverse

f (x) = 1 - \frac{1}{2} e^{- 2 b x}

- \frac{ln ( - 2 x + 2 )}{2 b}

Solution steps

y = 1 - \frac{1}{2} e^{- 2 b x}

Replace

x

with

y

x = 1 - \frac{1}{2} e^{- 2 b y}

Solve for

y, x = 1 - \frac{1}{2} e^{- 2 b y}

- \frac{ln ( - 2 x + 2 )}{2 b}

2 x + 3 y x + 2 y = 2

f (x) = 2083 x

f (x) = - arctan (x + 1)

f (x) = \frac{6}{2 x + 1}

f (x) = \frac{x - 3}{5} - 2

What is the inverse of f(x)=1-1/2 e^{-2bx} ?
The inverse of f(x)=1-1/2 e^{-2bx} is -(ln(-2x+2))/(2b)