What is the inverse of f(x)= x/(e^3)+e^4x+e ?

The inverse of f(x)= x/(e^3)+e^4x+e is (e^3x-e^4)/(1+e^7)

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inverse of f(x)= x/(e^3)+e^4x+e

inverse

f (x) = \frac{x}{e ^{3}} + e^{4} x + e

\frac{e ^{3} x - e ^{4}}{1 + e ^{7}}

Solution steps

y = \frac{x}{e ^{3}} + e^{4} x + e

Replace

x

with

y

x = \frac{y}{e ^{3}} + e^{4} y + e

Solve for

y, x = \frac{y}{e ^{3}} + e^{4} y + e

\frac{e ^{3} x - e ^{4}}{1 + e ^{7}}

f (x) = lo g_{3} (\frac{x + 6}{2}) + 1

y = \frac{1}{2} (1 + e^{x})

- ln (x + 2) + 1

f (x) = \frac{4 x}{3} + \frac{1}{2}

f (x) = 5 ln (1 + 8 x^{3})

What is the inverse of f(x)= x/(e^3)+e^4x+e ?
The inverse of f(x)= x/(e^3)+e^4x+e is (e^3x-e^4)/(1+e^7)