What is the inverse of D/(Dx)4x+10x^2 ?

The inverse of D/(Dx)4x+10x^2 is sqrt((x-4)/(10)),-sqrt((x-4)/(10))

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inverse of D/(Dx)4x+10x^2

inverse

\frac{D}{D x} 4 x + 10 x^{2}

\frac{x - 4}{10}, - \frac{x - 4}{10}

Solution steps

y = \frac{D}{D x} \cdot 4 x + 10 x^{2}

Replace

x

with

y

x = \frac{D}{Dy} \cdot 4 y + 10 y^{2}

Solve for

y, x = \frac{D}{Dy} 4 y + 10 y^{2}

\frac{x - 4}{10}, - \frac{x - 4}{10}

f (x) = 2 x^{\frac{5}{2}} + 4

7 - 3 x^{2} x - 3

f (x) = \frac{- x - 8}{8}

\frac{2}{2} \frac{2}{2}

\frac{4 ^{x} - 2 ^{2 x - 1}}{4 ^{x} + 1}

What is the inverse of D/(Dx)4x+10x^2 ?
The inverse of D/(Dx)4x+10x^2 is sqrt((x-4)/(10)),-sqrt((x-4)/(10))