What is the inverse of (1+sqrt(2))^n ?

The inverse of (1+sqrt(2))^n is (ln(n))/(ln(1+sqrt(2)))

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inverse of (1+sqrt(2))^n

inverse

(1 + 2)^{n}

\frac{ln ( n )}{ln ( 1 + 2 )}

Solution steps

y = (1 + 2)^{n}

Replace

n

with

y

n = (1 + 2)^{y}

Solve for

y, n = (1 + 2)^{y}

\frac{ln ( n )}{ln ( 1 + 2 )}

f (x) = x + 8 x

\frac{2 x + 1}{x + 1}

x (- x + 8)

f (x) = 2 \cdot x

f (x) = \frac{\frac{2}{x} - 3}{\frac{4}{x ^{2}} - 9}

What is the inverse of (1+sqrt(2))^n ?
The inverse of (1+sqrt(2))^n is (ln(n))/(ln(1+sqrt(2)))