What is the inverse of f(x)=(x^2-4)^{1/2} ?

The inverse of f(x)=(x^2-4)^{1/2} is sqrt(x^2+4),-sqrt(x^2+4)

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inverse of f(x)=(x^2-4)^{1/2}

inverse

f (x) = (x^{2} - 4)^{\frac{1}{2}}

x^{2} + 4, - x^{2} + 4

Solution steps

y = (x^{2} - 4)^{\frac{1}{2}}

Replace

x

with

y

x = (y^{2} - 4)^{\frac{1}{2}}

Solve for

y, x = (y^{2} - 4)^{\frac{1}{2}}

x^{2} + 4, - x^{2} + 4

f (x) = (x - 3) + 7

f (x) = (x - 3) + 2

V (x) = x^{3}

f (x) = f (x) = 6 x + 8 (x + 2)

1.2 + lo g_{2} (x + 10)

What is the inverse of f(x)=(x^2-4)^{1/2} ?
The inverse of f(x)=(x^2-4)^{1/2} is sqrt(x^2+4),-sqrt(x^2+4)