What is the inverse of f(x)=3.4-0.4x+0.06x^2 ?

The inverse of f(x)=3.4-0.4x+0.06x^2 is (40+sqrt(2400x-6560))/(12),(40-sqrt(2400x-6560))/(12)

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inverse of f(x)=3.4-0.4x+0.06x^2

inverse

f (x) = 3.4 - 0.4 x + 0.06 x^{2}

\frac{40 + 2400 x - 6560}{12}, \frac{40 - 2400 x - 6560}{12}

Solution steps

y = 3.4 - 0.4 x + 0.06 x^{2}

Replace

x

with

y

x = 3.4 - 0.4 y + 0.06 y^{2}

Solve for

y, x = 3.4 - 0.4 y + 0.06 y^{2}

\frac{40 + 2400 x - 6560}{12}, \frac{40 - 2400 x - 6560}{12}

f (x) = 15 + 3 r

f (x) = \frac{- 2}{2 x + 5}

f (x) = 6 + 4 x - 4

y = f (x) = \frac{x}{2} + 1

\frac{1}{4} ln (\frac{x - 2}{x + 1})

What is the inverse of f(x)=3.4-0.4x+0.06x^2 ?
The inverse of f(x)=3.4-0.4x+0.06x^2 is (40+sqrt(2400x-6560))/(12),(40-sqrt(2400x-6560))/(12)