What is the inverse of f(x)=x^2-12x+36,x>= 6 ?

The inverse of f(x)=x^2-12x+36,x>= 6 is 6+sqrt(x),6-sqrt(x)

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inverse of f(x)=x^2-12x+36,x>= 6

inverse

f (x) = x^{2} - 12 x + 36, x \geq 6

6 + x, 6 - x

Solution steps

y = x^{2} - 12 x + 36

Replace

x

with

y

x = y^{2} - 12 y + 36

Solve for

y, x = y^{2} - 12 y + 36

6 + x, 6 - x

f (x) = - x 3 + 6 x 2 - 9 x

\frac{3 x - 2}{x + 1}

f (x) = \frac{7 x - 6}{4 x + 3}

f (x) = 4 r + 16

2 + \frac{1}{x - 5}

What is the inverse of f(x)=x^2-12x+36,x>= 6 ?
The inverse of f(x)=x^2-12x+36,x>= 6 is 6+sqrt(x),6-sqrt(x)