What is the inverse of sqrt(x^2+9x-20) ?

The inverse of sqrt(x^2+9x-20) is (-9+sqrt(4x^2+161))/2 ,(-9-sqrt(4x^2+161))/2

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inverse of sqrt(x^2+9x-20)

inverse

x^{2} + 9 x - 20

\frac{- 9 + 4 x ^{2} + 161}{2}, \frac{- 9 - 4 x ^{2} + 161}{2}

Solution steps

y = x^{2} + 9 x - 20

Replace

x

with

y

x = y^{2} + 9 y - 20

Solve for

y, x = y^{2} + 9 y - 20

\frac{- 9 + 4 x ^{2} + 161}{2}, \frac{- 9 - 4 x ^{2} + 161}{2}

f (x) = \frac{2}{e - π} (x - π) - 1

\frac{s}{s ^{2} - 6 s - 7}

- 4 x^{2} + 32 x - 60

f (x) = \frac{9}{4 + x}

2 arctan (\frac{3}{u})

What is the inverse of sqrt(x^2+9x-20) ?
The inverse of sqrt(x^2+9x-20) is (-9+sqrt(4x^2+161))/2 ,(-9-sqrt(4x^2+161))/2