What is the inverse of f(x)=0.03x^2+245.5 ?

The inverse of f(x)=0.03x^2+245.5 is sqrt((100x-24550)/3),-sqrt((100x-24550)/3)

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inverse of f(x)=0.03x^2+245.5

inverse

f (x) = 0.03 x^{2} + 245.5

\frac{100 x - 24550}{3}, - \frac{100 x - 24550}{3}

Solution steps

y = 0.03 x^{2} + 245.5

Replace

x

with

y

x = 0.03 y^{2} + 245.5

Solve for

y, x = 0.03 y^{2} + 245.5

\frac{100 x - 24550}{3}, - \frac{100 x - 24550}{3}

1.29 x^{2000}

f (x) = \frac{( 7 x - 6 )}{x + 3}

f (x) = \frac{( 7 + 2 x )}{9 - 5 x}

10 + 4 x - 4

y = \frac{2 x - 3}{x + 1}

What is the inverse of f(x)=0.03x^2+245.5 ?
The inverse of f(x)=0.03x^2+245.5 is sqrt((100x-24550)/3),-sqrt((100x-24550)/3)