What is the inverse of f(x)=(2x-9)/(7x+1) ?

The inverse of f(x)=(2x-9)/(7x+1) is (-9-x)/(7x-2)

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inverse of f(x)=(2x-9)/(7x+1)

inverse

f (x) = \frac{2 x - 9}{7 x + 1}

\frac{- 9 - x}{7 x - 2}

Solution steps

y = \frac{2 x - 9}{7 x + 1}

Replace

x

with

y

x = \frac{2 y - 9}{7 y + 1}

Solve for

y, x = \frac{2 y - 9}{7 y + 1}

\frac{- 9 - x}{7 x - 2}

\frac{x + 5}{x + 14}

100 - 2 q

f (x) = \frac{5 x}{5}

+ 1 - ln (x - 2)

f (x) = 4 (- 2 x - 9)^{3}

What is the inverse of f(x)=(2x-9)/(7x+1) ?
The inverse of f(x)=(2x-9)/(7x+1) is (-9-x)/(7x-2)