What is the inverse of y=x^{1/5}-3 ?

The inverse of y=x^{1/5}-3 is x^5+15x^4+90x^3+270x^2+405x+243

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inverse of y=x^{1/5}-3

inverse

y = x^{\frac{1}{5}} - 3

x^{5} + 15 x^{4} + 90 x^{3} + 270 x^{2} + 405 x + 243

Solution steps

y = x^{\frac{1}{5}} - 3

Replace

x

with

y

x = y^{\frac{1}{5}} - 3

Solve for

y, x = y^{\frac{1}{5}} - 3

x^{5} + 15 x^{4} + 90 x^{3} + 270 x^{2} + 405 x + 243

f (x) = \frac{5 x + 8}{7}

\frac{- 4 x + 7}{5 + 9 x}

y = \frac{9}{5} (4 x + 3)

f (x) = arcsin (- \frac{6 π}{5})

y = 5 x + 9

What is the inverse of y=x^{1/5}-3 ?
The inverse of y=x^{1/5}-3 is x^5+15x^4+90x^3+270x^2+405x+243