What is the inverse of f(x)=(x^2+4)/(x+2) ?

The inverse of f(x)=(x^2+4)/(x+2) is (x+sqrt(x^2-4(4-2x)))/2 ,(x-sqrt(x^2-4(4-2x)))/2

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inverse of f(x)=(x^2+4)/(x+2)

inverse

f (x) = \frac{x ^{2} + 4}{x + 2}

\frac{x + x ^{2} - 4 ( 4 - 2 x )}{2}, \frac{x - x ^{2} - 4 ( 4 - 2 x )}{2}

Solution steps

y = \frac{x ^{2} + 4}{x + 2}

Replace

x

with

y

x = \frac{y ^{2} + 4}{y + 2}

Solve for

y, x = \frac{y ^{2} + 4}{y + 2}

\frac{x + x ^{2} - 4 ( 4 - 2 x )}{2}, \frac{x - x ^{2} - 4 ( 4 - 2 x )}{2}

f (- 4) = \frac{( x + 4 )}{( x + 6 )}

z (1)

x^{2} + 3

- 54

f (x) = \frac{( 2 + ( 4 x + 2 ) )}{( 2 x + 2 )}

What is the inverse of f(x)=(x^2+4)/(x+2) ?
The inverse of f(x)=(x^2+4)/(x+2) is (x+sqrt(x^2-4(4-2x)))/2 ,(x-sqrt(x^2-4(4-2x)))/2