What is the inverse of f(x)= 1/3 log_{10}(64+4x) ?

The inverse of f(x)= 1/3 log_{10}(64+4x) is (1000^x-64)/4

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inverse of f(x)= 1/3 log_{10}(64+4x)

inverse

f (x) = \frac{1}{3} lo g_{10} (64 + 4 x)

\frac{100 0 ^{x} - 64}{4}

Solution steps

y = \frac{1}{3} lo g_{10} (64 + 4 x)

Replace

x

with

y

x = \frac{1}{3} lo g_{10} (64 + 4 y)

Solve for

y, x = \frac{1}{3} lo g_{10} (64 + 4 y)

\frac{100 0 ^{x} - 64}{4}

f (x) = x^{2} + 5 x + 1

- 5 + 5 (x - 3)^{2}

y = 5 x - 7

y = 5 x - 8

f (x) = 2 sin (4 x)

What is the inverse of f(x)= 1/3 log_{10}(64+4x) ?
The inverse of f(x)= 1/3 log_{10}(64+4x) is (1000^x-64)/4