What is the inverse of f(x)=(x-6)^2,x<= 6 ?

The inverse of f(x)=(x-6)^2,x<= 6 is sqrt(x)+6,-sqrt(x)+6

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inverse of f(x)=(x-6)^2,x<= 6

inverse

f (x) = (x - 6)^{2}, x \leq 6

x + 6, - x + 6

Solution steps

y = (x - 6)^{2}

Replace

x

with

y

x = (y - 6)^{2}

Solve for

y, x = (y - 6)^{2}

x + 6, - x + 6

f (x) = 5 x^{\frac{3}{7}}

f (x) = 0 x + 5

\frac{5 x - 2}{2 x + 7}

y = \frac{x}{1 + 2 x}

y = 5 x - 2

What is the inverse of f(x)=(x-6)^2,x<= 6 ?
The inverse of f(x)=(x-6)^2,x<= 6 is sqrt(x)+6,-sqrt(x)+6