What is the inverse of f(x)=sqrt((x+8pi)/(2pi))-2 ?

The inverse of f(x)=sqrt((x+8pi)/(2pi))-2 is 2pix^2+8pix

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inverse of f(x)=sqrt((x+8pi)/(2pi))-2

inverse

f (x) = \frac{x + 8 π}{2 π} - 2

2 π x^{2} + 8 π x

Solution steps

y = \frac{x + 8 π}{2 π} - 2

Replace

x

with

y

x = \frac{y + 8 π}{2 π} - 2

Solve for

y, x = \frac{y + 8 π}{2 π} - 2

2 π x^{2} + 8 π x

\frac{1}{4} s^{4}

f (x) = \frac{7 x - 7}{7 x + 4}

2 (x + 2)^{2}

f (x) = - \frac{5}{3}

f (- 4) = \frac{x + 2}{x + 9}

What is the inverse of f(x)=sqrt((x+8pi)/(2pi))-2 ?
The inverse of f(x)=sqrt((x+8pi)/(2pi))-2 is 2pix^2+8pix