What is the inverse of f(x)=(x^2)/(x^2+4) ?

The inverse of f(x)=(x^2)/(x^2+4) is sqrt(-(4x)/(x-1)),-sqrt(-(4x)/(x-1))

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inverse of f(x)=(x^2)/(x^2+4)

inverse

f (x) = \frac{x ^{2}}{x ^{2} + 4}

- \frac{4 x}{x - 1}, - - \frac{4 x}{x - 1}

Solution steps

y = \frac{x ^{2}}{x ^{2} + 4}

Replace

x

with

y

x = \frac{y ^{2}}{y ^{2} + 4}

Solve for

y, x = \frac{y ^{2}}{y ^{2} + 4}

- \frac{4 x}{x - 1}, - - \frac{4 x}{x - 1}

f (x) = 6 x - 180

f (x) = \frac{( - x + 2 )}{x + 1}

f (x) = x (2 x + 500)

F (x) = 3 x + 10

\frac{1}{z - 0.5}

What is the inverse of f(x)=(x^2)/(x^2+4) ?
The inverse of f(x)=(x^2)/(x^2+4) is sqrt(-(4x)/(x-1)),-sqrt(-(4x)/(x-1))