What is the inverse of f(x)=(x^2-3^2) ?

The inverse of f(x)=(x^2-3^2) is sqrt(x+9),-sqrt(x+9)

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inverse of f(x)=(x^2-3^2)

inverse

f (x) = (x^{2} - 3^{2})

x + 9, - x + 9

Solution steps

y = x^{2} - 3^{2}

Replace

x

with

y

x = y^{2} - 3^{2}

Solve for

y, x = y^{2} - 3^{2}

x + 9, - x + 9

f (x) = \frac{6 x - 8}{5 x + 8}

f (- 4) = \frac{x + 2}{x + 8}

f (x) = \frac{3 x - 2}{4 x - 3}

\frac{a + 2}{a - 1}

f (7) = \frac{( 2 x + 1 )}{3}

What is the inverse of f(x)=(x^2-3^2) ?
The inverse of f(x)=(x^2-3^2) is sqrt(x+9),-sqrt(x+9)