What is the inverse of f(x)=(x+8)^2-3 ?

The inverse of f(x)=(x+8)^2-3 is sqrt(x+3)-8,-sqrt(x+3)-8

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inverse of f(x)=(x+8)^2-3

inverse

f (x) = (x + 8)^{2} - 3

x + 3 - 8, - x + 3 - 8

Solution steps

y = (x + 8)^{2} - 3

Replace

x

with

y

x = (y + 8)^{2} - 3

Solve for

y, x = (y + 8)^{2} - 3

x + 3 - 8, - x + 3 - 8

f (x) = - \frac{x}{4} + \frac{3}{2}

y = \frac{5 + x}{4 - 2 x}

f (y) = \frac{1}{3} (2^{3 x + 1}) - 1

3 ln (x + 4 - 1), x > 0

f (x) = (x^{3} + 1)^{0.5}

What is the inverse of f(x)=(x+8)^2-3 ?
The inverse of f(x)=(x+8)^2-3 is sqrt(x+3)-8,-sqrt(x+3)-8