What is the inverse of g(x)=(7x-2)/(3x+4) ?

The inverse of g(x)=(7x-2)/(3x+4) is (-2-4x)/(3x-7)

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inverse of g(x)=(7x-2)/(3x+4)

inverse

g (x) = \frac{7 x - 2}{3 x + 4}

\frac{- 2 - 4 x}{3 x - 7}

Solution steps

y = \frac{7 x - 2}{3 x + 4}

Replace

x

with

y

x = \frac{7 y - 2}{3 y + 4}

Solve for

y, x = \frac{7 y - 2}{3 y + 4}

\frac{- 2 - 4 x}{3 x - 7}

f (x) = \frac{9 x + 5}{x - 3} = y

y = \frac{2 x + 3}{x - 1}

\frac{4 x - 1}{x + 8}

\frac{2}{( s + 2 ) ^{2}}

f (x) = \frac{x}{9 x - 1}

What is the inverse of g(x)=(7x-2)/(3x+4) ?
The inverse of g(x)=(7x-2)/(3x+4) is (-2-4x)/(3x-7)