What is the inverse of (x-4)/(x^2+8x+16) ?

The inverse of (x-4)/(x^2+8x+16) is (-8x+1+sqrt(-32x+1))/(2x),(-8x+1-sqrt(-32x+1))/(2x)

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inverse of (x-4)/(x^2+8x+16)

inverse

\frac{x - 4}{x ^{2} + 8 x + 16}

\frac{- 8 x + 1 + - 32 x + 1}{2 x}, \frac{- 8 x + 1 - - 32 x + 1}{2 x}

Solution steps

y = \frac{x - 4}{x ^{2} + 8 x + 16}

Replace

x

with

y

x = \frac{y - 4}{y ^{2} + 8 y + 16}

Solve for

y, x = \frac{y - 4}{y ^{2} + 8 y + 16}

\frac{- 8 x + 1 + - 32 x + 1}{2 x}, \frac{- 8 x + 1 - - 32 x + 1}{2 x}

f (x) = \frac{7}{4 x + 5}

q (x) = - 2 (- 3 x + 2)

f (x) = 2 e^{3 x^{2}}

y = lo g_{6} (3 x - 1) = 2

f (x) = \frac{13}{2} x - 4

What is the inverse of (x-4)/(x^2+8x+16) ?
The inverse of (x-4)/(x^2+8x+16) is (-8x+1+sqrt(-32x+1))/(2x),(-8x+1-sqrt(-32x+1))/(2x)