What is the inverse of f(x)=2+sqrt(4-x^2) ?

The inverse of f(x)=2+sqrt(4-x^2) is sqrt(-x^2+4x),-sqrt(-x^2+4x)

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inverse of f(x)=2+sqrt(4-x^2)

inverse

f (x) = 2 + 4 - x^{2}

- x^{2} + 4 x, - - x^{2} + 4 x

Solution steps

y = 2 + 4 - x^{2}

Replace

x

with

y

x = 2 + 4 - y^{2}

Solve for

y, x = 2 + 4 - y^{2}

- x^{2} + 4 x, - - x^{2} + 4 x

f (x) = \frac{2}{3 x + 4}

f (x) = \frac{2 x - 6}{5 x - 1}

\frac{x ^{2} - x + 1}{x ^{2} + 1}

\frac{8 x}{3}

y = \frac{60 x}{1 x ^{2} + 100}

What is the inverse of f(x)=2+sqrt(4-x^2) ?
The inverse of f(x)=2+sqrt(4-x^2) is sqrt(-x^2+4x),-sqrt(-x^2+4x)