What is the inverse of 1/((x-2)^2)+1 ?

The inverse of 1/((x-2)^2)+1 is sqrt(1/(x-1))+2,-sqrt(1/(x-1))+2

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inverse of 1/((x-2)^2)+1

inverse

\frac{1}{( x - 2 ) ^{2}} + 1

\frac{1}{x - 1} + 2, - \frac{1}{x - 1} + 2

Solution steps

y = \frac{1}{( x - 2 ) ^{2}} + 1

Replace

x

with

y

x = \frac{1}{( y - 2 ) ^{2}} + 1

Solve for

y, x = \frac{1}{( y - 2 ) ^{2}} + 1

\frac{1}{x - 1} + 2, - \frac{1}{x - 1} + 2

2 (x + 7) - 3

f (x) = \frac{2}{2 - x}

f (n) = 3 + n^{3}

1 + 3.22 lo g_{34} (x)

y = \frac{11 π}{45}

What is the inverse of 1/((x-2)^2)+1 ?
The inverse of 1/((x-2)^2)+1 is sqrt(1/(x-1))+2,-sqrt(1/(x-1))+2