What is the inverse of f(x)=((x+1))/((x+7)) ?

The inverse of f(x)=((x+1))/((x+7)) is (1-7x)/(x-1)

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inverse of f(x)=((x+1))/((x+7))

inverse

f (x) = \frac{( x + 1 )}{( x + 7 )}

\frac{1 - 7 x}{x - 1}

Solution steps

y = \frac{x + 1}{x + 7}

Replace

x

with

y

x = \frac{y + 1}{y + 7}

Solve for

y, x = \frac{y + 1}{y + 7}

\frac{1 - 7 x}{x - 1}

f (x) = x^{2} + 1

y = x^{3} - 2

(x, - 2), (- 5, - 5)

(\frac{1}{2}, 10), (0, \frac{- 1}{5})

f (x) = 1 - ∣ x ∣

What is the inverse of f(x)=((x+1))/((x+7)) ?
The inverse of f(x)=((x+1))/((x+7)) is (1-7x)/(x-1)