What is the inverse of y=f(x)=2sqrt(x-3)+1 ?

The inverse of y=f(x)=2sqrt(x-3)+1 is (x^2+1)/4-x/2+3

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inverse of y=f(x)=2sqrt(x-3)+1

inverse

y = f (x) = 2 x - 3 + 1

\frac{x ^{2} + 1}{4} - \frac{x}{2} + 3

Solution steps

y = 2 x - 3 + 1

Replace

x

with

y

x = 2 y - 3 + 1

Solve for

y, x = 2 y - 3 + 1

\frac{x ^{2} + 1}{4} - \frac{x}{2} + 3

f (x) = lo g_{10} (9 x)

g (x) = - 1 + (x - 2)^{5}

3 x + 3

y = \frac{3}{x + 4}

y = - 4 x^{(6)}

What is the inverse of y=f(x)=2sqrt(x-3)+1 ?
The inverse of y=f(x)=2sqrt(x-3)+1 is (x^2+1)/4-x/2+3