What is the inverse of f(x)=(10x)^{((1/5))}-2 ?

The inverse of f(x)=(10x)^{((1/5))}-2 is (x^5+10x^4+40x^3+80x^2+80x+32)/(10)

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inverse of f(x)=(10x)^{((1/5))}-2

inverse

f (x) = (10 x)^{((\frac{1}{5}))} - 2

\frac{x ^{5} + 10 x ^{4} + 40 x ^{3} + 80 x ^{2} + 80 x + 32}{10}

Solution steps

y = (10 x)^{\frac{1}{5}} - 2

Replace

x

with

y

x = (10 y)^{\frac{1}{5}} - 2

Solve for

y, x = (10 y)^{\frac{1}{5}} - 2

\frac{x ^{5} + 10 x ^{4} + 40 x ^{3} + 80 x ^{2} + 80 x + 32}{10}

f (x) = \frac{( 9 x + 8 )}{x - 3}

f (x) = 4^{x} \cdot 300

\frac{- 2}{x + 1}

f (x) = 5 + 4 x - 8

y = 2 + e^{- 2 x}

What is the inverse of f(x)=(10x)^{((1/5))}-2 ?
The inverse of f(x)=(10x)^{((1/5))}-2 is (x^5+10x^4+40x^3+80x^2+80x+32)/(10)