What is the inverse of (3x^{1+1/2})/8 ?

The inverse of (3x^{1+1/2})/8 is (4\sqrt[3]{3}\sqrt[3]{x^2})/3

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inverse of (3x^{1+1/2})/8

inverse

\frac{3 x ^{1 + \frac{1}{2}}}{8}

\frac{4 3 3 3 x ^{2}}{3}

Solution steps

y = \frac{3 x ^{1 + \frac{1}{2}}}{8}

Replace

x

with

y

x = \frac{3 y ^{1 + \frac{1}{2}}}{8}

Solve for

y, x = \frac{3 y ^{1 + \frac{1}{2}}}{8}

\frac{4 3 3 3 x ^{2}}{3}

e^{- 3 t}

\frac{x ^{3} - 11 x ^{2} + 24 x}{x ^{2} - 8 x}

f (x) = 3 a + 5

4 (\frac{1}{2})^{x}

f (x) = \frac{60 x}{0.0001 x ^{2} + 100}

What is the inverse of (3x^{1+1/2})/8 ?
The inverse of (3x^{1+1/2})/8 is (4\sqrt[3]{3}\sqrt[3]{x^2})/3