What is the inverse of f(x)=4x^2-4x+5 ?

The inverse of f(x)=4x^2-4x+5 is (1+sqrt(x-4))/2 ,(1-sqrt(x-4))/2

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inverse of f(x)=4x^2-4x+5

inverse

f (x) = 4 x^{2} - 4 x + 5

\frac{1 + x - 4}{2}, \frac{1 - x - 4}{2}

Solution steps

y = 4 x^{2} - 4 x + 5

Replace

x

with

y

x = 4 y^{2} - 4 y + 5

Solve for

y, x = 4 y^{2} - 4 y + 5

\frac{1 + x - 4}{2}, \frac{1 - x - 4}{2}

1 - x + 10

ln (x) + 1

f (x) = lo g_{4} (\frac{1}{4 x - 3})

f (x) = f (x) = 1.9737 (1000)

\frac{- 1}{2} lo g_{5} (\frac{1}{x + 3})

What is the inverse of f(x)=4x^2-4x+5 ?
The inverse of f(x)=4x^2-4x+5 is (1+sqrt(x-4))/2 ,(1-sqrt(x-4))/2