What is the inverse of f(x)= 3/(sqrt(2+x)) ?

The inverse of f(x)= 3/(sqrt(2+x)) is 9/(x^2)-2

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inverse of f(x)= 3/(sqrt(2+x))

inverse

f (x) = \frac{3}{2 + x}

\frac{9}{x ^{2}} - 2

Solution steps

y = \frac{3}{2 + x}

Replace

x

with

y

x = \frac{3}{2 + y}

Solve for

y, x = \frac{3}{2 + y}

\frac{9}{x ^{2}} - 2

- \frac{( x - 11 )}{14}, x \leq \frac{14}{11}

f (x) = \frac{9}{x} - 5

k - 1

ln (x) - 6

y = 5^{(x)} + 7

What is the inverse of f(x)= 3/(sqrt(2+x)) ?
The inverse of f(x)= 3/(sqrt(2+x)) is 9/(x^2)-2